document.write( "Question 936976: How many ounces of pure acid should be added to 35 oz of 40% acid to make 70% acid solution? \n" ); document.write( "

Algebra.Com's Answer #570430 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = ounces of pure acid to be added
\n" ); document.write( " $\"+.4%2A35+=+14+\"$ ounces of pure acid in 40%
\n" ); document.write( "solution
\n" ); document.write( "--------------
\n" ); document.write( " $\"+%28+x+%2B+14+%29+%2F+%28+x+%2B+35+%29+=+.7+\"$
\n" ); document.write( " $\"+x+%2B+14+=+.7%2A%28+x+%2B+35+%29+\"$
\n" ); document.write( " $\"+x+%2B+14+=+.7x+%2B+24.5+\"$
\n" ); document.write( " $\"+.3x+=+10.5+\"$
\n" ); document.write( " $\"+x+=+35+\"$
\n" ); document.write( "35 ounces of pure acid needs to be added
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+x+%2B+14+%29+%2F+%28+x+%2B+35+%29+=+.7+\"$
\n" ); document.write( " $\"+%28+35+%2B+14+%29+%2F+%28+35+%2B+35+%29+=+.7+\"$
\n" ); document.write( " $\"+49+%2F+70+=+.7+\"$
\n" ); document.write( " $\"+49+=+.7%2A70+\"$
\n" ); document.write( " $\"+49+=+49+\"$
\n" ); document.write( "OK \n" ); document.write( "

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