document.write( "Question 936892: David was 25 when his daughter was born. Now his age exceeds 4 times his daughter's age by 10 years. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #570365 by Edwin McCravy(20056)\"\" \"About 
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David was 25 when his daughter was born.
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document.write( "That means David is always 25 years older than his daughter.\r\n" );
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document.write( "David's age now = Daughter's age now + 25\r\n" );
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document.write( "Let daughter's age now = x\r\n" );
document.write( "Then David's age now = x+25 \r\n" );
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\n" ); document.write( "Now his age exceeds 4 times his daughter's age by 10 years.
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document.write( "x + 25 = 4x + 10\r\n" );
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document.write( "Solve that to get daughter's age and then add 25 to get David's age.\r\n" );
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document.write( "Edwin
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