document.write( "Question 936901: Mr. alvarado is 20 years older than his son. In 5 years, he will be 5 years more than twice as old as his son will then be. find the present ages.
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #570353 by srinivas.g(540)\"\" \"About 
You can put this solution on YOUR website!
let x,y be the present ages of Mr. alvarado and his sons
\n" ); document.write( " Mr. alvarado is 20 years older than his son.
\n" ); document.write( " hence
\n" ); document.write( " x= y+20..........eq(1)
\n" ); document.write( "In years , alvarado age will be = x+5
\n" ); document.write( " his son's age = y+5
\n" ); document.write( " In 5 years, he will be 5 years more than twice as old as his son
\n" ); document.write( " (x+5)= 2(y+5)+5
\n" ); document.write( " x+5 = 2*y+2*5 +5
\n" ); document.write( " x+5 = 2y+10+5
\n" ); document.write( " x+5= 2y+15
\n" ); document.write( " x= 2y+10
\n" ); document.write( " but x= y+20 from eq(1)
\n" ); document.write( " 2y+10 =y+20
\n" ); document.write( " 2y-y+10 =20
\n" ); document.write( " y+10 = 20
\n" ); document.write( " y= 10
\n" ); document.write( " present age of son = 10
\n" ); document.write( " present age of alvarado = 10+20 =30 years
\n" ); document.write( " \n" ); document.write( "
\n" );