document.write( "Question 936890: Please help solve this equation: (4x^-2 y^1/3)^3/2
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Algebra.Com's Answer #570346 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
\"a%5E0+=+1\"
\n" ); document.write( "\"%28+x%5Em+%29%28+x%5En+%29+=+x%5E%28+m+%2B+n+%29\"
\n" ); document.write( "\"x%5Em%2Fx%5En=x%5E%28m-n%29\"
\n" ); document.write( "\"%28a%5Ep%29%5Eq+=+a%5E%28p%2Aq%29\" ***
\n" ); document.write( "\"%28xy%29%5En+=+x%5En%2Ay%5En\"
\n" ); document.write( "x^(1/n) = \"root%28n%2Cx%29\"
\n" ); document.write( "x^(m/n) = \"root%28n%2Cx%5Em%29\"***
\n" ); document.write( ".........
\n" ); document.write( "(4^1x^-2^1y^1/3)^3/2 = 4^(3/2)x^(-3) - 2^(3/2)y^(1/2) = 8/x^3 - 2√2√y
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\n" ); document.write( "4^(3/2) = \"root%282%2C4%5E3%29\" = 8
\n" ); document.write( "2^(3/2) = \"root%282%2C2%5E3%29+=+sqrt%288%29\" = 2√2
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