document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79468>Question 79468</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A flat piece of wood with an area of 27 sq ft, and perimeter of 21 ft.  How do I calculate the dimensions? I'm totally clueless.  Thanks for our help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #57034 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=57034\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X*Y=27 X=27/Y<BR>\n" );
document.write( "2X+2Y=21<BR>\n" );
document.write( "2(27/Y)+2Y=21<BR>\n" );
document.write( "54/Y+2Y=21<BR>\n" );
document.write( "(54+2Y^2)/Y=21 CROSS MULTIPLY<BR>\n" );
document.write( "54+2Y^2=21Y<BR>\n" );
document.write( "2Y^2-21Y+54=0<BR>\n" );
document.write( "(2Y-9)(Y-6)=0<BR>\n" );
document.write( "2Y-9=0<BR>\n" );
document.write( "2Y=9<BR>\n" );
document.write( "Y=9/2<BR>\n" );
document.write( "Y=4.5 ANSWER.<BR>\n" );
document.write( "Y-6=0<BR>\n" );
document.write( "Y=6 ANSWER.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "6*4.5=27<BR>\n" );
document.write( "27=27<BR>\n" );
document.write( "2*4.5+2*6=21<BR>\n" );
document.write( "9+12=21<BR>\n" );
document.write( "21=21<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );