document.write( "Question 936776: Solve for x & y. 2/x-3/y=-5 4/x+6/y=14 Thanks for your help. \n" ); document.write( "
Algebra.Com's Answer #570313 by MathTherapy(10552)\"\" \"About 
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Solve for x & y. 2/x-3/y=-5 4/x+6/y=14 Thanks for your help.
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document.write( "\"2%2Fx+-+3%2Fy+=+-+5\" ------- eq (i)
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document.write( "\"4%2Fx+%2B+6%2Fy+=+14\" ------- eq (ii)
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document.write( "Let \"a+=+1%2Fx\", and \"b+=+1%2Fy\"
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document.write( "Then \"2%2Fx+-+3%2Fy+=+-+5\" becomes: 2a – 3b = - 5 ------ eq (iii)
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document.write( "Also, \"4%2Fx+%2B+6%2Fy+=+14\" becomes: 4a + 6b = 14 ------- eq (iv)
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document.write( "4a – 6b = - 10 -------- Multiplying eq (iii) by 2 ----- eq (v)
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document.write( "8a = 4 ------- Adding eqs (v) & (iv)
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document.write( "a = \"4%2F8\", or \"1%2F2\" \r
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document.write( "\"2%281%2F2%29+-+3b+=+-+5\" -------- Substituting ½ for a in eq (iii) 
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document.write( "1 – 3b = - 5 
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document.write( "– 3b = - 5 – 1 
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document.write( "– 3b = - 6
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document.write( "b = \"%28-+6%29%2F%28-+3%29\", or 2\r
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document.write( "Since \"system%28a+=+%281%2F2%29_and%2Ca+=+1%2Fx%29\", then \"1%2F2+=+1%2Fx\"
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document.write( "\"x+=+2\" ------ Cross-multiplying\r
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document.write( "Since \"system%28b+=+2_and%2Cb+=+1%2Fy%29\", then \"2+=+1%2Fy\"
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document.write( "2y = 1 ------ Cross-multiplying
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document.write( "\"y+=+1%2F2\"\r
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document.write( "\"highlight_green%28system%28x+=+2_and%2Cy+=+1%2F2%29%29\" \n" );
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