document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936727>Question 936727</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE HELP ME I AM STUCK.....<BR>\n" );
document.write( "AN ARITHMETIC PROGRESSION SERIES HAS THE FIRST TERM 4 AND THE COMMON DIFFERENCE OF 3 .IF THE SUM OF ALL INTEGERS IS 375.HOW MANY TERMS ARE THERE?<BR>\n" );
document.write( "PLEASE SOLVE IT AND EXPLAIN ME TOO  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #570218 by </B><A HREF=/tutors/aboutme.mpl?userid=Danielshinmath><B>Danielshinmath(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Danielshinmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Danielshinmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=570218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum is 4n+3*(n-1)=4n+3n-3=375, where n is the amount of terms and 4 represents thee first term. The 3 represents the common difference.<BR>\n" );
document.write( "if 4n+3n-3=375, that means 7n=375+3, which equals 7n=378. Then you get the answer n-378/7, or 54. </SPAN>\n" );
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