document.write( "Question 79387: How do I plot points with coordinates (2,3), (3,4), (4,5) on a graph? Would I be able to give the coordinates of another point with the same property? I have no idea of what to do here. Could somone possible explain the result step by step in order for me to understand the problem, Thank You \n" ); document.write( "
Algebra.Com's Answer #57016 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! THERE SRE 2 WAYS TO SOLVE THIS PROBLEM ALGEBRACIALLY & GRAPHICALLY. \n" ); document.write( "ALGEBRACIALLY WE NEED TO FIND THE SLOPE \n" ); document.write( "(Y2-Y1)/(X2-X1) \n" ); document.write( "(4-3)/(3-2)=1/1=1 FOR THE SLOPE OF THIS LINE. \n" ); document.write( "NOW WE SUBSTITUTE 1 SET OF X & Y POINTS AND FIND THE Y INTERCEPT (b) IN THE LINE EQUATION Y=mX+b WHERE (m)=SLOPE & (b)=Y INTERCEPT. \n" ); document.write( "3=1*2+b \n" ); document.write( "3=2+b \n" ); document.write( "b=3-2 \n" ); document.write( "b=1 THUS THE Y INTERCEPT IS 1. \n" ); document.write( "NOW WE HAVE THE LINE EQUATION OF \n" ); document.write( "Y=X+1. \n" ); document.write( "NOW TO FIND ANY OTHER POINT WE SET X TO A NEW VALUE SAY -2 & SOLVE FOR Y \n" ); document.write( "Y=-2+1 \n" ); document.write( "Y=-1 OR THIS POINT IS (-2,-1) \n" ); document.write( "------------------------------------------------------------- \n" ); document.write( "HAVING THE EQUATION OF THE LINE Y=X+1 WE CAN NOW GRAPH THIS LINE THUS: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |