document.write( "Question 79387: How do I plot points with coordinates (2,3), (3,4), (4,5) on a graph? Would I be able to give the coordinates of another point with the same property? I have no idea of what to do here. Could somone possible explain the result step by step in order for me to understand the problem, Thank You \n" ); document.write( "
Algebra.Com's Answer #57016 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
THERE SRE 2 WAYS TO SOLVE THIS PROBLEM ALGEBRACIALLY & GRAPHICALLY.
\n" ); document.write( "ALGEBRACIALLY WE NEED TO FIND THE SLOPE
\n" ); document.write( "(Y2-Y1)/(X2-X1)
\n" ); document.write( "(4-3)/(3-2)=1/1=1 FOR THE SLOPE OF THIS LINE.
\n" ); document.write( "NOW WE SUBSTITUTE 1 SET OF X & Y POINTS AND FIND THE Y INTERCEPT (b) IN THE LINE EQUATION Y=mX+b WHERE (m)=SLOPE & (b)=Y INTERCEPT.
\n" ); document.write( "3=1*2+b
\n" ); document.write( "3=2+b
\n" ); document.write( "b=3-2
\n" ); document.write( "b=1 THUS THE Y INTERCEPT IS 1.
\n" ); document.write( "NOW WE HAVE THE LINE EQUATION OF
\n" ); document.write( "Y=X+1.
\n" ); document.write( "NOW TO FIND ANY OTHER POINT WE SET X TO A NEW VALUE SAY -2 & SOLVE FOR Y
\n" ); document.write( "Y=-2+1
\n" ); document.write( "Y=-1 OR THIS POINT IS (-2,-1)
\n" ); document.write( "-------------------------------------------------------------
\n" ); document.write( "HAVING THE EQUATION OF THE LINE Y=X+1 WE CAN NOW GRAPH THIS LINE THUS:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+y+=x+%2B1%29+\" (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = x +1).
\n" ); document.write( "
\n" ); document.write( "
\n" );