document.write( "Question 936688: a plane takes off and travels at an angle of 40 degrees north of east at 110 mph for 2 hours. it then adjusts its path to head 10 degrees west of north and travels in that direction for half an hour at a speed of of 100 mph. Approximately how far was the plane from its starting point? \n" ); document.write( "
Algebra.Com's Answer #570155 by TimothyLamb(4379)\"\" \"About 
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s = d/t
\n" ); document.write( "d = st
\n" ); document.write( "---
\n" ); document.write( "first leg distance:
\n" ); document.write( "b = 110*2 = 220 miles
\n" ); document.write( "---
\n" ); document.write( "second leg distance:
\n" ); document.write( "c = 100*1/2 = 50 miles
\n" ); document.write( "---
\n" ); document.write( "angle A between legs b and c:
\n" ); document.write( "40 + 80 = 120 degrees
\n" ); document.write( "---
\n" ); document.write( "use The Law of Cosines to find side a, the third side of the triangle:
\n" ); document.write( "---
\n" ); document.write( "aa = bb + cc - 2bc cosA
\n" ); document.write( "aa = 220*220 + 50*50 - 2*220*50*cos(120)
\n" ); document.write( "a = sqrt( 220*220 + 50*50 - 2*220*50*cos(120) )
\n" ); document.write( "a = 248.797106092
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "249 miles
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