document.write( "Question 79438: Complete the ordered pairs so that each is a solution for the given problem: 3x+4y=12 (_,0),(8/3,_) \n" ); document.write( "
Algebra.Com's Answer #57015 by funmath(2933)\"\" \"About 
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Complete the ordered pairs so that each is a solution for the given problem: 3x+4y=12 (_,0),(8/3,_)
\n" ); document.write( "Ordered pairs are in alphabetical order (x,y)
\n" ); document.write( "For (_,0) let y=0 and solve for x.
\n" ); document.write( "3x+4(0)=12
\n" ); document.write( "3x+0=12
\n" ); document.write( "3x=12
\n" ); document.write( "3x/3=12/3
\n" ); document.write( "x=4 So the ordered pair is (4,0)
\n" ); document.write( "For (8/3,_) let x=8/3 and solve for y
\n" ); document.write( "3(8/3)+4y=12
\n" ); document.write( "8+4y=12
\n" ); document.write( "8-8+4y=12-8
\n" ); document.write( "4y=4
\n" ); document.write( "4y/4=4/4
\n" ); document.write( "y=1 So the ordered pair is (8/3,1)
\n" ); document.write( "Happy Calculating!!!! \n" ); document.write( "
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