document.write( "Question 936665: Michael had $5.25 in nickels and quarters. If he had 15 more nickels than quarters, how many coins of each type did he have? \r
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Algebra.Com's Answer #570131 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! x the number of Quarters (25 CENTS in a each Qarter) \n" ); document.write( "25x + 5(x+15) = 525cents (CENTS makes Sense) \n" ); document.write( "30x = 450 \n" ); document.write( "x = 15, number of Quarters. Nickels 30 \n" ); document.write( ".... \n" ); document.write( "Checking.. \n" ); document.write( "25(15) + 5(30) = 375 + 150 = 525cents or $5.25 \n" ); document.write( " |