document.write( "Question 936652: How many liters of a 10% solution of acid should be mixed with 60% solution of acid to obtain 20 liters of 50% solution.
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Algebra.Com's Answer #570111 by ewatrrr(24785)\"\" \"About 
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x the amount of 60% solution
\n" ); document.write( ".60x + .10(20L - x) = .50(20L)
\n" ); document.write( "x = .40(20L)/.5 = 16L, the amount of 60% solution
\n" ); document.write( "20L - x, the amount of 10% solution
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