document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936648>Question 936648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman bought 65 lb. of fertilizer to spread over her rectangular backyard. if she spread it at a rate of 20 lb. to 1000 ft. and the length of the yard exceeds the width by 10 ft., what were the dimensions of the yard?\r<BR>\n" );
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document.write( "This is a word problem in a certain chapter in our book which deals all about Quadratic Equations. I hope you could help me out. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #570108 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=570108\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  A woman bought 65 lb. of fertilizer to spread over her rectangular backyard. if she spread it at a rate of 20 lb. to 1000 ft. and the length of the yard exceeds the width by 10 ft., what were the dimensions of the yard?<BR>\n" );
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document.write( "width = w ft<BR>\n" );
document.write( "length = w+10 ft<BR>\n" );
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document.write( "Area = w(w+10) = w^2 + 10w sq. ft.<BR>\n" );
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document.write( "Assuming that the 65 lb of fertilizer covers her yard,<BR>\n" );
document.write( "area of yard = 65/(20 lb/1000 ft) = (65/20)*1000 = 3250 sq yds<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "w^2 + 10w - 3250 = 0<BR>\n" );
document.write( "w = 175.35 ft(width)<BR>\n" );
document.write( "w+10 = 185.35 ft (length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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