document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936545>Question 936545</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is less than 10 another. twice thier sum is 60. <BR>\n" );
document.write( "find the number?\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #570104 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=570104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the 'one number'<BR>\n" );
document.write( "x - y = 10<BR>\n" );
document.write( "2(x+y) = 60<BR>\n" );
document.write( "......<BR>\n" );
document.write( "2(x - y = 10)<BR>\n" );
document.write( "<u>2x + 2y = 60</u><BR>\n" );
document.write( "4x = 80<BR>\n" );
document.write( "x = 20  and y = 10 </SPAN>\n" );
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