document.write( "Question 936616: The rate of change represents the gas mileage in miles per gallon. Between which two measurements was the gas's mileage least?\r
\n" ); document.write( "\n" ); document.write( "Miles Driven 0 60 150 170 230 260\r
\n" ); document.write( "\n" ); document.write( "Gas Used(gal) 0 2 5 6 9 11
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Algebra.Com's Answer #570064 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "The rate of change represents the gas mileage in miles per gallon. Between which two measurements was the gas's mileage least?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Miles Driven .....|\"0\" |\"60\"| \"150\"| \"170\"|\"+230\"|\"+260\"|
\n" ); document.write( "Gas Used(gal) ...|\"0+\"..|\"2\"|....\"+5\"|....\"+6\"|.... \"9\"| ....\"11\"|
\n" ); document.write( "-------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "rate of change:
\n" ); document.write( "\"%28150-60%29%2F%285-2%29=90%2F3=30\"
\n" ); document.write( "\"%28170-150%29%2F%286-5%29=20%2F1=20\"
\n" ); document.write( "\"%28230-170%29%2F%289-6%29=60%2F3=20\"
\n" ); document.write( "\"%28260-230%29%2F%2811-9%29=30%2F2=15\"\r
\n" ); document.write( "\n" ); document.write( "so, we have\r
\n" ); document.write( "\n" ); document.write( "Miles Driven .....|\"0\" |\"60\"| \"150\"| \"170\"|\"+230\"|\"+260\"|
\n" ); document.write( "Gas Used(gal) ...|\"0+\"..|\"2\"|....\"+5\"|....\"+6\"|.... \"9\"| ....\"11\"|
\n" ); document.write( "-------------------------------------------------------
\n" ); document.write( "------------------------\"30\"| \"30\"|....\"20\"|....\"20\"|....\"15\"|\r
\n" ); document.write( "\n" ); document.write( "Between \"9\" and \"11\" the gas's mileage was least.\r
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