document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936574>Question 936574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A candy mix sells for $2.20 per kilogram. It contains chocolates worth $1.80 per kilogram and other candy worth $3.00 per kilogram. How much of each are in the 15 kilograms of the mixture?<BR>\n" );
document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #570021 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=570021\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I see a major fault in the problem description.  You are examining how to mix $2.20 per kg with $1.80 per kg and result in a price of mixture at $3.00 per kg.  NOT POSSIBLE.  Neither material to be mixed is as high priced as the intended mixture.  $3.00 per kg is NOT in range of 2.20 to 1.80.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Recheck your problem description from your learning material carefully.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "....Again, understand, the problem description is WRONG. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );