document.write( "Question 936473: how do you find the inverse of a logarithm function
\n" ); document.write( "my problem question is y=4log3(x)+1
\n" ); document.write( "the base or small number in the log function is 3
\n" ); document.write( "i know you have to substitute x for y when you are doing the inverse and i got to the step x= 4log3(y)+1 but i am stuck on what to do after you substitute it.
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Algebra.Com's Answer #569942 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
find the inverse of a logarithm function
\n" ); document.write( "my problem question is y=4log3(x)+1
\n" ); document.write( "Starting with what you have
\n" ); document.write( "\"4log%283%2C%28y%29%29+%2B+1+=+x\"
\n" ); document.write( "\"4log%283%2C%28y%29%29+=+x+-+1\"
\n" ); document.write( "\"log%283%2C%28y%5E4%29%29+=+x+-+1\"
\n" ); document.write( "Write the exponent equiv of logs
\n" ); document.write( " \"y%5E4+=+3%5E%28%28x-1%29%29\"
\n" ); document.write( "find the 4th root of both sides
\n" ); document.write( "\"y+=+%283%5E%28%28x-1%29%29%29%5E%281%2F4%29\"
\n" ); document.write( "\"y+=+3%5E%28%28x-1%29%2F4%29\"; exponent is \"%28%28x-1%29%2F4%29\"
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