document.write( "Question 936415: the sum of the ages of 4 people born 4 years apart is 88 whatis the age of the youngest \n" ); document.write( "
Algebra.Com's Answer #569869 by srinivas.g(540)\"\" \"About 
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let ages of 4 people born 4 years apart be x,x+4,x+8,x+12
\n" ); document.write( "sum of their ages = 88
\n" ); document.write( " x+(x+4)+(x+8)+(x+12)=88
\n" ); document.write( " x+x+4+x+8+x+12 = 88
\n" ); document.write( " 4x+24= 88
\n" ); document.write( " move 24 to the right
\n" ); document.write( " 4x = 88-24
\n" ); document.write( " 4x = 64
\n" ); document.write( " divide with 4 on both sides
\n" ); document.write( " \"+4x%2F4++=64%2F4\"
\n" ); document.write( " \"+x=16\"
\n" ); document.write( " x= 16
\n" ); document.write( " x+4 = 20
\n" ); document.write( " x+8 = 24
\n" ); document.write( " x+12 = 28
\n" ); document.write( " age of youngest is 16 years
\n" ); document.write( "
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