document.write( "Question 936400: the sum of 3 consecutive whole numbers is 2013. what is the sum of all the digits of these numbers? \n" ); document.write( "
Algebra.Com's Answer #569851 by srinivas.g(540)![]() ![]() You can put this solution on YOUR website! let x-1,x,x+1 be the three consecutive whole numbers \n" ); document.write( " their sum =(x-1)+x+((x+1) \n" ); document.write( " =x-1+x+x+1 \n" ); document.write( " =3x \n" ); document.write( "but the sum is 2013 \n" ); document.write( " 3x= 2013 \n" ); document.write( " divide with on both sides \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " x=671 \n" ); document.write( " x-1 =671-1 =670 \n" ); document.write( " x+1 = 671+1 =672 \n" ); document.write( " so the three consecutive whole numbers are 670,671,672 \n" ); document.write( " \n" ); document.write( " |