document.write( "Question 936400: the sum of 3 consecutive whole numbers is 2013. what is the sum of all the digits of these numbers? \n" ); document.write( "
Algebra.Com's Answer #569851 by srinivas.g(540)\"\" \"About 
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let x-1,x,x+1 be the three consecutive whole numbers
\n" ); document.write( " their sum =(x-1)+x+((x+1)
\n" ); document.write( " =x-1+x+x+1
\n" ); document.write( " =3x
\n" ); document.write( "but the sum is 2013
\n" ); document.write( " 3x= 2013
\n" ); document.write( " divide with on both sides
\n" ); document.write( " \"+3x%2F3++=+2013%2F3\"
\n" ); document.write( " \"+x=+671\"
\n" ); document.write( " x=671
\n" ); document.write( " x-1 =671-1 =670
\n" ); document.write( " x+1 = 671+1 =672
\n" ); document.write( " so the three consecutive whole numbers are 670,671,672
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