document.write( "Question 936376: Calculate the number of sides a regular polygon has if an interior angle is five times the size of an exterior angle. \n" ); document.write( "
Algebra.Com's Answer #569841 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "Suppose the interior angle is \"x\" degrees.
\n" ); document.write( "Then the exterior angle is \"180+-+x\" degrees.\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+5%2A%28180-x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+900+-+5x\"\r
\n" ); document.write( "\n" ); document.write( "\"6x+=+900\" \r
\n" ); document.write( "\n" ); document.write( "\"+x+=+150\" degrees.\r
\n" ); document.write( "\n" ); document.write( "So exterior angle = \"30\" degrees.\r
\n" ); document.write( "\n" ); document.write( "If the polygon has \"n\" sides (and n angles) the sum of its exterior angles is \"30%2An\"\r
\n" ); document.write( "\n" ); document.write( "But the exterior angles of a polygon add to \"360+\" degrees
\n" ); document.write( "So, \"30%2An+=+360\" => \"n+=+12\".\r
\n" ); document.write( "\n" ); document.write( "ANSWER: the polygon has \"12\" sides. \r
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