document.write( "Question 79384: Complete the ordered pairs so that each is a solution for the given equation.
\n" ); document.write( "3x+4y=12 (0,_), (_,3/4), (_,0), (8/3,_) I do not have a clue as to where to start with this problem. I would really appreciate it if someone would please explain it step by step to help me understand the problem. \n" ); document.write( "
Algebra.Com's Answer #56984 by tutorcecilia(2152)\"\" \"About 
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In ordered pairs, the first number is always the x-term and the second number is always the y-term. So (x, y) can be (1, 0) and the x=1; y=0
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\n" ); document.write( "In this problem, identify either the x or the y-term, plug it into the problem and solve for the missing term:
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\n" ); document.write( "\n" ); document.write( "(0,_), so x=0 and the y-term is missing:
\n" ); document.write( "3x+4y=12
\n" ); document.write( "3(0)+4y=12
\n" ); document.write( "0+4y=12
\n" ); document.write( "4y=12
\n" ); document.write( "4y/4=12/4
\n" ); document.write( "y=3
\n" ); document.write( "So, the point is (0,3)
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\n" ); document.write( "(_,3/4), so the x-term is missing and y=3/4
\n" ); document.write( "3x+4(3/4)=12
\n" ); document.write( "3x+3=12
\n" ); document.write( "3x+3-3=12-2
\n" ); document.write( "3x=9
\n" ); document.write( "3x/3=9/3
\n" ); document.write( "x=3
\n" ); document.write( "So, the point is (3, 3/4) \n" ); document.write( "
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