document.write( "Question 936359: I need help with this question. \r
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document.write( "1. Write the inverse equation of y=2^x+1 ( The x+1 is the exponent. I tried solving it and my answer was y^-1= lnx-ln2/ln2\r
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document.write( "b. Provide a table of values of y=2^x+1 and its inverse. (I will know how to do this if you can help me with the first part)\r
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document.write( "c. What are the asymptotes for each graph? Be sure to identify if it is horizontal or vertical. (The question wants the asymptote for y=2^x+1 and the asymptote for the inverse of y=2^x+1 \n" );
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Algebra.Com's Answer #569797 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! y=2^(x+1) is very different from y=2^x+1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You want this equation: y=2^(x+1). Rendering makes it appear, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The quick way to get inverse, \n" ); document.write( "Switch x and y roles. \n" ); document.write( "Keeping in base 2... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can find a table of values for your given exponential function, since this is a very elementary level task. You will find a horizontal limit of y=0.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The given exponential function graph, BASE IS 2. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Domain and range switch for the inverse. \n" ); document.write( " \n" ); document.write( "The system unfortunately is not fully displaying the inverse graph. The asymptote should be understood and appear as y=0, a vertical asymptote. \n" ); document.write( " |