document.write( "Question 936334: How would you solve; 7^(2x+1)=4^(x-2) \n" ); document.write( "
Algebra.Com's Answer #569763 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"7%5E%282x%2B1%29=4%5E%28x-2%29\" .....since \"7%5E%282x%2B1%29=7%5E%282x%29%2A7\" and \"4%5E%28x-2%29=4%5Ex%2F4%5E2\", we have\r
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\n" ); document.write( "\n" ); document.write( "\"7%5E%282x%29%2A7=4%5Ex%2F4%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"7%5E%282x%29%2A7=4%5Ex%2F4%5E2\" \r
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\n" ); document.write( "\n" ); document.write( "\"7%5E%282x%29%2F4%5Ex=1%2F%287%2A4%5E2%29\" .........use a logarithm\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%287%5E%282x%29%2F4%5Ex%29%29=log%28%281%2F%287%2A4%5E2%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%287%5E%282x%29%29%29-log%28%284%5Ex%29%29=log%281%29-log%28%287%2A4%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( " ...\"log%28%281%29%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%282log%28%287%29%29-log%28%282%5E2%29%29%29=2log%28%282%5E2%29%29-log%28%287%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%282log%28%287%29%29-2log%28%282%29%29%29=4log%28%282%29%29-log%28%287%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%284log%28%282%29%29-log%28%287%29%29%29%2F%282%28log%28%287%29%29-log%28%282%29%29%29%29\"\r
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