document.write( "Question 936236: How can I prove this?
\n" ); document.write( "[sin(x)-cos(x)+1] / [sin(x)+cos(x)-1] = [sin(x)+1] / cos(x) \n" ); document.write( "
Algebra.Com's Answer #569731 by oscargut(2103)\"\" \"About 
You can put this solution on YOUR website!
[sin(x)-cos(x)+1] / [sin(x)+cos(x)-1] = [sin(x)+1] / cos(x)\r
\n" ); document.write( "\n" ); document.write( "[sin(x)-cos(x)+1]cos(x) = [sin(x)+1][sin(x)+cos(x)-1] \r
\n" ); document.write( "\n" ); document.write( "sin(x)cos(x)-cos(x)cos(x)+cos(x) = sin(x)sin(x)+sin(x)cos(x)-sin(x)+sin(x)+cos(x)-1\r
\n" ); document.write( "\n" ); document.write( "-cos(x)cos(x) = sin(x)sin(x)-1\r
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\n" ); document.write( "\n" ); document.write( " 0= sin(x)sin(x)+cos(x)cos(x)-1\r
\n" ); document.write( "\n" ); document.write( "And the last equation is true\r
\n" ); document.write( "\n" ); document.write( "If you need more help or details you can contact me at:
\n" ); document.write( "mthman@gmail.com
\n" ); document.write( "Thanks
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