document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936275>Question 936275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are the steps that will take to transform the equation 10x+2y=25 into the equation y=-5x+25/2 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569715 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What are the steps that will take to transform the equation 10x+2y=25 into the equation y = -5x+25/2<BR>\n" );
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document.write( "Starting with 10x+2y = 25<BR>\n" );
document.write( "Subtract 10x from both sides to get:<BR>\n" );
document.write( "2y = -10x + 25<BR>\n" );
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document.write( "Divide both sides by 2 to get:<BR>\n" );
document.write( "y = -5x + 25/2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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