document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936272>Question 936272</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle of largest area is cut out from a circle. what percent of area is lost as trimming </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569710 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a rectangle of largest area is cut out from a circle. <BR>\n" );
document.write( "what percent of area is lost as trimming<BR>\n" );
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document.write( "That rectangle is a square with diagonal equal to the diameter of the circle.<BR>\n" );
document.write( "Area of the circle:: pi(d/2)^2 (pi/4)d^2<BR>\n" );
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document.write( "Area of the square:: (d/sqrt(2))^2 = (1/2)d^2<BR>\n" );
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document.write( "Percent lost = (area of square)/(area of circle) = (1/2)d^2/(pi/4)d^2<BR>\n" );
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document.write( "= (1/2)/(pi/4) = 2/pi = 64%<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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