document.write( "Question 936125: Ali has 20 gallons of 20% sulfuric acid solution. How much 100% sulfuric acid solution must add to make a solution that is steady 50% sulfuric acid. \n" ); document.write( "
Algebra.Com's Answer #569707 by Theo(13342)\"\" \"About 
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let y = the number of gallons of 100% acid solution that you have to add to get a 50% acid solution.\r
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\n" ); document.write( "\n" ); document.write( "you have 20 gallons of 20% acid solution.\r
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\n" ); document.write( "\n" ); document.write( "your equation will be:\r
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\n" ); document.write( "\n" ); document.write( ".2 * 20 + y = .5 * (20 + y)\r
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\n" ); document.write( "\n" ); document.write( "20 + y is the total amount of gallons of solution that you will have when you are done.\r
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\n" ); document.write( "\n" ); document.write( "simplify this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "4 + y = 10 + .5 * y\r
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\n" ); document.write( "\n" ); document.write( "subtract .5 * y from both sides of this equation and subtract 4 from both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "y - .5 * y = 10 - 4\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( ".5 * y = 6\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by .5 to get:\r
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\n" ); document.write( "\n" ); document.write( "y = 12\r
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\n" ); document.write( "\n" ); document.write( "you will need 12 gallons of 100% acid solution added to 20 gallons of 20% acid solution to get 32 gallons of 50% acid.\r
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\n" ); document.write( "\n" ); document.write( "the number of gallons of pure acid in the new solution will be .2 * 20 + 12 which is equal to 4 + 12 = 16\r
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\n" ); document.write( "\n" ); document.write( "16 / 32 = 50%\r
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\n" ); document.write( "\n" ); document.write( "numbers look good.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that you will need to add 12 gallons of 100% sulfuric acid to 20 gallons of 20% sulfuric acid to make 32 gallons of 50% sulfuric acid.\r
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