document.write( "Question 79378: can you help me solve by completing the square?\r
\n" ); document.write( "\n" ); document.write( "x^2-6x-3=0
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Algebra.Com's Answer #56967 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
solve by completing the square?
\n" ); document.write( "x^2-6x-3=0
\n" ); document.write( "Rearrange:
\n" ); document.write( "x^2-6x+? = 3+?
\n" ); document.write( "Now, complete the square
\n" ); document.write( "x^2-6x+(6/2)^2 = 3+(6/2)^2
\n" ); document.write( "Factor the left side and evaluate the right side:
\n" ); document.write( "(x-3)^2 = 12
\n" ); document.write( "Take the square root of both sides to get:
\n" ); document.write( "x-3 = 2sqrt3 or x-3=-2sqrt3
\n" ); document.write( "Solve for x to get:
\n" ); document.write( "x=3+2sqrt3 or x=3-2sqrt3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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