document.write( "Question 79378: can you help me solve by completing the square?\r
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document.write( "x^2-6x-3=0 \n" );
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Algebra.Com's Answer #56967 by stanbon(75887) ![]() You can put this solution on YOUR website! solve by completing the square? \n" ); document.write( "x^2-6x-3=0 \n" ); document.write( "Rearrange: \n" ); document.write( "x^2-6x+? = 3+? \n" ); document.write( "Now, complete the square \n" ); document.write( "x^2-6x+(6/2)^2 = 3+(6/2)^2 \n" ); document.write( "Factor the left side and evaluate the right side: \n" ); document.write( "(x-3)^2 = 12 \n" ); document.write( "Take the square root of both sides to get: \n" ); document.write( "x-3 = 2sqrt3 or x-3=-2sqrt3 \n" ); document.write( "Solve for x to get: \n" ); document.write( "x=3+2sqrt3 or x=3-2sqrt3 \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |