document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936223>Question 936223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> transform the quadratic function y= -2x^2-12x-10 into vertex form. find the vertex, x and y intercepts. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569669 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569669\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y= -2x^2-12x-10  P(0, -10) y-intercept<BR>\n" );
document.write( "y = -2(x+3)^2 + 18  - 10<BR>\n" );
document.write( "y = -2(x+3)^2 + 8<BR>\n" );
document.write( "V(-3,8)<BR>\n" );
document.write( "...... <BR>\n" );
document.write( "0 = -2(x+3)^2 + 8<BR>\n" );
document.write( "4 =(x+3)^2<BR>\n" );
document.write( "± 2 = x+3<BR>\n" );
document.write( "-3 ± 2 = x<BR>\n" );
document.write( "P(-5,0) and P(-1,0) x-intercepts<BR>\n" );
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document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );