document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936228>Question 936228</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The current in a simple electrical circuit varies inversely as the resistance. If the current is 50amps when the resistance is 10ohms, find the current if the resistance is 50hms.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569667 by </B><A HREF=/tutors/aboutme.mpl?userid=srinivas.g><B>srinivas.g(540)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=srinivas.g><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=srinivas.g><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  initial current (c1) = 50 amps<BR>\n" );
document.write( "final current   = c2<BR>\n" );
document.write( "initial resistance(R1)= 10 ohms<BR>\n" );
document.write( "final resistance(R2) = 50 ohms<BR>\n" );
document.write( " relation b/w current and resistance is inverse<BR>\n" );
document.write( " hence<BR>\n" );
document.write( "    c1 x r1 = c2 xr2<BR>\n" );
document.write( "   50 *10 =c2*50<BR>\n" );
document.write( "      divide with 50 on both sides<BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=50%2A10%2F50+=c2%2A50%2F50 ALIGN=MIDDLE  ALT=\"50%2A10%2F50+=c2%2A50%2F50\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "       10 =c2<BR>\n" );
document.write( " current  = 10 amps <BR>\n" );
document.write( "   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );