document.write( "Question 936201: Hank has a total of $175 in $5 and $20 bills. The number of $5 bills he has is 3 more than 4 times the number of $20 bills. How many of each type of bill does Hank have? \n" ); document.write( "

Algebra.Com's Answer #569635 by srinivas.g(540) $\"\"$ $\"About$

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let x be the no of $ 5 bills
\n" ); document.write( "let y be the no of $ 20 bills
\n" ); document.write( "The number of $5 bills he has is 3 more than 4 times the number of $20 bills
\n" ); document.write( "hence
\n" ); document.write( " x= 4*y+3
\n" ); document.write( "but total is $175
\n" ); document.write( " hence 175= x*5 +y*20
\n" ); document.write( " put x= 4y+3 in the above equation
\n" ); document.write( " 175 = (4y+3)*5+y*20
\n" ); document.write( " 175 = 4y*5+3*5+20y
\n" ); document.write( " 175 =20y+15+20y
\n" ); document.write( " 175 = 20y+20y+15
\n" ); document.write( " 175 = 40y+15
\n" ); document.write( " subtract 15 on both sides
\n" ); document.write( " 175-15 =40y+15-15
\n" ); document.write( " 160 =40y
\n" ); document.write( " divide with 40 on both sides
\n" ); document.write( " $\"160%2F40+=+40y%2F40\"$
\n" ); document.write( " $\"4+=+y\"$
\n" ); document.write( " so no of $20 bills(y)= 4
\n" ); document.write( " no of $ 5 bills(x) = 4*4+3
\n" ); document.write( " =16+3
\n" ); document.write( " =19
\n" ); document.write( "Result: no of $ 5 bills = 19 & no of $20 bills = 4 \n" ); document.write( "

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