document.write( "Question 936159: Use the substitution y=3^x to find the values of x which satisfy the equation
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document.write( "3^(2x+2)-10*3^(x) +1=0\r
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document.write( "I tried: 3^(2)*3^(x) + 3^(2) -10*3^(x) + 1 =0
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document.write( "Substituted in y: 9y + 9 - 10y + 1 = 0
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document.write( "which became: -y=-9 then y=9
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document.write( "so 3^x = 9 therefore x is 2 or so I thought.
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document.write( "The textbook answer given is -2 and 0. \r
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document.write( "Please could you help me and explain where I went wrong? Thank you. \n" );
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Algebra.Com's Answer #569614 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Use the substitution y=3^x to find the values of x which satisfy the equation \n" ); document.write( "3^(2x+2)-10*3^(x) +1=0\r \n" ); document.write( "\n" ); document.write( "I tried: 3^(2)*3^(x) + 3^(2) -10*3^(x) + 1 =0 \n" ); document.write( "It's 3^2*3^(2x) -10*3^x + 1 = 0 \n" ); document.write( "--> 9y^2 - 10y + 1 = 0 \n" ); document.write( "====================================== \n" ); document.write( "You had the right idea, but having 2 answers should make you expect a quadratic. \n" ); document.write( "-------------------------------------- \n" ); document.write( "Substituted in y: 9y + 9 - 10y + 1 = 0 \n" ); document.write( "which became: -y=-9 then y=9 \n" ); document.write( "so 3^x = 9 therefore x is 2 or so I thought. \n" ); document.write( "The textbook answer given is -2 and 0. \n" ); document.write( " \n" ); document.write( " |