document.write( "Question 936149: How much water must be added to 400L of mixture that is 80% alcohol to reduce it to a 60% mixture? \n" ); document.write( "
Algebra.Com's Answer #569593 by srinivas.g(540)![]() ![]() You can put this solution on YOUR website! initial quantity of mixture = 400 L \n" ); document.write( "alcohol % = 80 % \n" ); document.write( "quantity of alcohol in the mixture = 80 % of 400 L \n" ); document.write( " = \n" ); document.write( " = \n" ); document.write( " = \n" ); document.write( "Let X be the quantity of water added to the mixture \n" ); document.write( " final quantity of the mixture = 400+ x \n" ); document.write( "alcohol 5 in final mixture = 60 % \n" ); document.write( "quantity of alcohol in final mixture = 60 % of (400+x) \n" ); document.write( " = \n" ); document.write( " = \n" ); document.write( "\n" ); document.write( "quantity of alcohol in the initial mixture and final mixture is same \n" ); document.write( " \n" ); document.write( " multiply with 5 on both sides \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " move 1200 to the left \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " divide with 3 on both sides \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Result: Quantity of water added = 133.33 L \n" ); document.write( " |