document.write( "Question 936149: How much water must be added to 400L of mixture that is 80% alcohol to reduce it to a 60% mixture? \n" ); document.write( "
Algebra.Com's Answer #569593 by srinivas.g(540)\"\" \"About 
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initial quantity of mixture = 400 L
\n" ); document.write( "alcohol % = 80 %
\n" ); document.write( "quantity of alcohol in the mixture = 80 % of 400 L
\n" ); document.write( " =\"++%2880%2F100%29%2A400\"
\n" ); document.write( " =\"80%2A4\"
\n" ); document.write( " =\"320\" L
\n" ); document.write( "Let X be the quantity of water added to the mixture
\n" ); document.write( " final quantity of the mixture = 400+ x
\n" ); document.write( "alcohol 5 in final mixture = 60 %
\n" ); document.write( "quantity of alcohol in final mixture = 60 % of (400+x)
\n" ); document.write( " =\"+%2860%2F100%29%2A%28400%2Bx%29\"
\n" ); document.write( " = \"%283%2F5%29%2A%28400%2Bx%29\"\r
\n" ); document.write( "\n" ); document.write( "quantity of alcohol in the initial mixture and final mixture is same
\n" ); document.write( " \"+320++=++%283%2F5%29%2A%28400%2Bx%29\"
\n" ); document.write( " multiply with 5 on both sides
\n" ); document.write( " \"320+%2A5+=+%283%2F5%29%2A%28400%2Bx%29%2A5\"
\n" ); document.write( " \"1600+=+3%2A%28400%2Bx%29\"
\n" ); document.write( " \"1600+=+3%2A400%2B3%2Ax\"
\n" ); document.write( " \"1600+=1200%2B3x\"
\n" ); document.write( " move 1200 to the left
\n" ); document.write( " \"1600-1200+=3x\"
\n" ); document.write( " \"400+=3x\"
\n" ); document.write( " divide with 3 on both sides
\n" ); document.write( " \"400%2F3++=3x%2F3\"
\n" ); document.write( " \"400%2F3+=+x\"
\n" ); document.write( " \"x+=133.33+L\"
\n" ); document.write( "Result: Quantity of water added = 133.33 L
\n" ); document.write( "
\n" );