document.write( "Question 935903: My watch is set to show the correct time at 12 noon on Wednesday. It gains 4 minutes every 3 hours.
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document.write( "a. What time does the watch show when the correct time is 12 noon on Friday, assuming the watch has not been reset again?
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document.write( "b. The watch is reset again to show the correct time at 12 noon on Friday. What is the correct time when the watch is showing 19:40 on Friday night? \n" );
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Algebra.Com's Answer #569557 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! My watch is set to show the correct time at 12 noon on Wednesday. \n" ); document.write( " It gains 4 minutes every 3 hours. \n" ); document.write( "a. What time does the watch show when the correct time is 12 noon on Friday, assuming the watch has not been reset again? \n" ); document.write( "From 12 noon Wednesday to 12 noon Friday, it's 48 hrs \n" ); document.write( "It gains 4 min every three hrs, therefore \n" ); document.write( "4 * \n" ); document.write( "It will show 01:04 Pm \n" ); document.write( ": \n" ); document.write( "b. The watch is reset again to show the correct time at 12 noon on Friday. \n" ); document.write( " What is the correct time when the watch is showing 19:40 on Friday night? \n" ); document.write( "Find the relationship between the correct elapsed time to the watch time \n" ); document.write( "3 hrs 4 min to 3 hrs \n" ); document.write( "184/180 = 1.022\r \n" ); document.write( "\n" ); document.write( "convert 7 hr 40 min to min: 7*60 + 40 = 460 min \n" ); document.write( "let t = the correct elapsed time in minutes \n" ); document.write( "1.0222t = 460 \n" ); document.write( "t = 460/ 1.222 \n" ); document.write( "t = 450 min \n" ); document.write( "convert to hrs and min 450 min = 7 hrs 30 min, \n" ); document.write( "Correct time 19:30, when the watch says 19:40 \n" ); document.write( " \n" ); document.write( " |