document.write( "Question 936095: (3 + sqrt24) / (6 sqrt8)
\n" ); document.write( "A. (3 sqrt2 + 4 sqrt3) / 24
\n" ); document.write( "B. (1 + sqrt3) / 2
\n" ); document.write( "C. (3 + 8 sqrt3) / 6
\n" ); document.write( "D. -15 / (36 sqrt2 - 48 sqrt3)
\n" ); document.write( "e. none of these
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Algebra.Com's Answer #569545 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%283%2Bsqrt%2824%29%29%2F%286%2Asqrt%288%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2Bsqrt%284%2A6%29%29%2F%286%2Asqrt%284%2A2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2Bsqrt%284%29%2Asqrt%286%29%29%2F%286%2Asqrt%284%29%2Asqrt%282%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2B2%2Asqrt%286%29%29%2F%2812%2Asqrt%282%29%29\"\r
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\n" ); document.write( "\n" ); document.write( " Multiply top and bottom by \"sqrt%282%29\" to rationalize the denominator.\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2Asqrt%282%29%2B2%2Asqrt%286%29%2Asqrt%282%29%29%2F%2812%2Asqrt%282%29%2Asqrt%282%29%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2Asqrt%282%29%2B4%2Asqrt%283%29%29%2F%2824%29\"\r
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\n" ); document.write( "\n" ); document.write( "So, \r
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\n" ); document.write( "\n" ); document.write( "Which means the answer is Choice A\r
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\n" ); document.write( "\n" ); document.write( "If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).\r
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\n" ); document.write( "\n" ); document.write( "Alternatively, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Any amount is greatly appreciated as it helps me a lot. This donation is to support free tutoring. Thank you.\r
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\n" ); document.write( "\n" ); document.write( "Jim\r
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