document.write( "Question 936092: Solve the logarithmic equation: log2 4+log2 x=6
\n" ); document.write( "I got x=2, is this correct?
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Algebra.Com's Answer #569541 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( " \"log%282%2C+4%29%2Blog%282%2C+x%29=6\"\r
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\n" ); document.write( "\n" ); document.write( " \"log%282%2C+4x%29=6\"...in base \"10\"\r
\n" ); document.write( "\n" ); document.write( " \"log%284x%29%2Flog%282%29=6\"\r
\n" ); document.write( "\n" ); document.write( "\"log%284x%29=6log%282%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%284x%29=log%282%5E6%29\" ...if log same, then\r
\n" ); document.write( "\n" ); document.write( "\"4x=2%5E6\" \r
\n" ); document.write( "\n" ); document.write( "\"4x=64\" \r
\n" ); document.write( "\n" ); document.write( "\"x=64%2F4\" \r
\n" ); document.write( "\n" ); document.write( "\"x=16\"
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