document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936089>Question 936089</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 7 cm longer than the width.if the perimeter is 62 cm,find the length.<BR>\n" );
document.write( "Please help me! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569539 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length is 7 cm longer than the width, so L = W+7. We'll use the perimeter formula P = 2*(L+W) where the given perimeter is P = 62\r<BR>\n" );
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document.write( "P = 2*(L+W)\r<BR>\n" );
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document.write( "P = 2*(W+7+W) ... plug in L = W+7\r<BR>\n" );
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document.write( "62 = 2*(2W+7) ... plug in P = 62. Solve for W\r<BR>\n" );
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document.write( "62 = 4W + 14\r<BR>\n" );
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document.write( "62-14 = 4W\r<BR>\n" );
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document.write( "48 = 4W\r<BR>\n" );
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document.write( "4W = 48\r<BR>\n" );
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document.write( "W = 48/4\r<BR>\n" );
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document.write( "W = 12\r<BR>\n" );
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document.write( "Since W = 12, we can use this to find L\r<BR>\n" );
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document.write( "L = W+7\r<BR>\n" );
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document.write( "L = 12+7\r<BR>\n" );
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document.write( "L = 19\r<BR>\n" );
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document.write( "So the length is 19 cm.\r<BR>\n" );
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document.write( "Jim\r<BR>\n" );
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