document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936078>Question 936078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me figure out this problem. The perimeter of a square porch is 3 more than the area. Find the length of a side, it's area, and it's perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569517 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a square porch is 3 more than the area. Find the length of a side, it's area, and it's perimeter.<BR>\n" );
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document.write( "Perimeter = 4s where s is an edge of the square<BR>\n" );
document.write( "Area = s^2<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "4s = s^2 + 3<BR>\n" );
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document.write( "s^2 - 4s + 3 = 0<BR>\n" );
document.write( "(s-3)(s-1) = 0<BR>\n" );
document.write( "s = 1 or s = 3<BR>\n" );
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document.write( "If s = 1, area = 1 ; perimeter = 4<BR>\n" );
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document.write( "If s = 3, area = 9 ; perimeter = 12<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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