document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=936046>Question 936046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A grocer has two kinds of tea: one selling for 80 cents a pound and the other selling for 60 cents a pound. How many pounds of each kind must he use to make 50 pounds worth 74 cents a pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569467 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569467\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A grocer has two kinds of tea: one selling for 80 cents a pound and the other selling for 60 cents a pound. How many pounds of each kind must he use to make 50 pounds worth 74 cents a pound?<BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "80x + 60(50-x) = 74*50<BR>\n" );
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document.write( "80x + 60*50 - 60x = 74*50<BR>\n" );
document.write( "----<BR>\n" );
document.write( "20x = 14*50<BR>\n" );
document.write( "x = 35 lbs (amt. of 80 cent tea to use)<BR>\n" );
document.write( "50-x = 15 lbs (amt. of 60 cent tean to use)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "---------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );