document.write( "Question 935990: Write (\"+log%28+3%2C+7+%29+%2A+log%28+4%2C+3+%29+%2A+log%28+7%2C+6+%29+\") as a single logarithm. \n" ); document.write( "
Algebra.Com's Answer #569412 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
this was a doozy, but i think i was able to figure it out.\r
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\n" ); document.write( "\n" ); document.write( "by the log conversion formula, you get:\r
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\n" ); document.write( "\n" ); document.write( "\"log%283%2C7%29+=+log%287%29%2Flog%283%29\" and \"log%284%2C3%29+=+log%283%29%2Flog%284%29\" and \"log%286%2C7%29+=+log%286%29%2Flog%287%29\"\r
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\n" ); document.write( "\n" ); document.write( "you get the following equation:\r
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\n" ); document.write( "\n" ); document.write( "(\"+log%28+3%2C+7+%29+%2A+log%28+4%2C+3+%29+%2A+log%28+7%2C+6+%29+\") = \"log%287%29%2Flog%283%29+%2A+log%283%29%2Flog%284%29+%2A+log%286%29%2Flog%287%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%287%29\" in the numerator and denominator cancel out, and \"log%283%29\" in the numerator and denominator cancel out and you are left with \"log%286%29+%2F+log%284%29\"\r
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\n" ); document.write( "\n" ); document.write( "by the log base conversion formula, you get:\r
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\n" ); document.write( "\n" ); document.write( "\"log%284%2C6%29+=+log%286%29+%2F+log%284%29\" and so your final solution is:\r
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\n" ); document.write( "\n" ); document.write( "(\"+log%28+3%2C+7+%29+%2A+log%28+4%2C+3+%29+%2A+log%28+7%2C+6+%29+\" = \"+log%284%2C6%29\".\r
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\n" ); document.write( "\n" ); document.write( "to confirm the solution is correct, you have to go back to the log conversion formulas.\r
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\n" ); document.write( "\n" ); document.write( "\"+log%284%2C6%29\".= \"log%286%29%2Flog%284%29\" = 1.29248125.\r
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\n" ); document.write( "\n" ); document.write( "(\"+log%28+3%2C+7+%29+%2A+log%28+4%2C+3+%29+%2A+log%28+7%2C+6+%29+\") = \"log%287%29%2Flog%283%29+%2A+log%283%29%2Flog%284%29+%2A+log%286%29%2Flog%287%29\" = 1.29248125.\r
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\n" ); document.write( "\n" ); document.write( "they give you the same value, so they're equivalent.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that the expression becomes \"log%284%2C6%29\"\r
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