document.write( "Question 936000: A research assistant made 160 mg of radioactive sodium (Na^24) and found that there was only 20 mg left 45 h later.\r
\n" ); document.write( "\n" ); document.write( "(a) What is the half-life of Na^24?\r
\n" ); document.write( "\n" ); document.write( "(b) If the laboratory requires 100 mg of Na^24 12 hours from now, how much Na^24 should the research assistant make now? (Ignore the 20mg she currently has)
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Algebra.Com's Answer #569409 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
General model is \"N=N%5Bo%5De%5E%28-kt%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"ln%28N%29=ln%28N%5Bo%5D%29-kt\"
\n" ); document.write( "\"ln%28N%29-ln%28N%5Bo%5D%29=-kt\"
\n" ); document.write( "\"kt=ln%28N%5Bo%5D%29-ln%28N%29\"
\n" ); document.write( "\"k=%281%2Ft%29ln%28N%5Bo%5D%2Fln%28N%29%29\"------use this to find the value for k.\r
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\n" ); document.write( "\n" ); document.write( "\"k=%281%2F45%29%28ln%28160%2F20%29%29\"
\n" ); document.write( "\"k=%281%2F45%29ln%288%29\"
\n" ); document.write( "\"highlight%28k=0.046%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can return to this one, \"kt=ln%28N%5Bo%5D%29-ln%28N%29\" , to determine the half-life.
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\n" ); document.write( "\"t=%281%2Fk%29ln%28N%5Bo%5D%2FN%29\"
\n" ); document.write( "\"t=%281%2Fk%29ln%282%29\"
\n" ); document.write( "\"t=%281%2F0.046%29ln%282%29\"
\n" ); document.write( "\"highlight%28t%5Bhalf%5D=15.07%29\", maybe more accuracy than reasonable.\r
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\n" ); document.write( "\n" ); document.write( "Your more specific decay model is \"N=N%5Bo%5De%5E%28-0.046t%29\".
\n" ); document.write( "Now you have a known N but you want to solve for \"N%5Bo%5D\".
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