document.write( "Question 935989: A rancher wants to use 400 feet of fencing to enclose a rectangular area of 5100 square feet. What dimensions should the rectangle have? \n" ); document.write( "
Algebra.Com's Answer #569407 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "A rancher wants to use 400 feet of fencing to enclose a rectangular area of 5100 square feet. What dimensions should the rectangle have?
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Let length be L, and width, W
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document.write( "Since perimeter = 2(L + W), then: 2(L + W) = 400
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document.write( "2(L + W) = 2(200)
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document.write( "L + W = 200_____W = 200 – L -------- eq (i)
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document.write( "Since area = 5,100 sq ft, and area = LW, then it can be said that: L(200 – L) = 5,100
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document.write( "\"200L+-+L%5E2+=+5100\"
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document.write( "\"L%5E2+-+200L+%2B+5100+=+0\"
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document.write( "(L - 170)(L - 30) = 0
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document.write( "L – 170 = 0					OR					L - 30 = 0
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document.write( "L, or length = 170 feet			OR					L = 30\r
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document.write( "If length = 170, then width = 200 – 170, or 30 feet
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document.write( "If length = 30, then width = 200 – 30, or 170 feet\r
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document.write( "Therefore, dimensions of rectangle are: \"highlight_green%28system%28170_by%2C30%29%29\"  
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document.write( "You can do the check!! 
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