document.write( "Question 935985: A canoe took 3 hours to travel up stream and 2 hours to travel the same distance down stream. If the distance was 12 miles each way, what was the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #569402 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "A canoe took 3 hours to travel up stream and 2 hours to travel the same distance down stream. If the distance was 12 miles each way, what was the speed of the current?
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Let speed in still water be S, and speed of current, C
\n" ); document.write( "Then upstream equation is: \"S+-+C+=+12%2F3\"________S - C = 4 ------ eq (i)
\n" ); document.write( "Also, downstream equation is: \"S+%2B+C+=+12%2F2\"_____S + C = 6 ------ eq (ii)
\n" ); document.write( "2S = 10 ------ Adding eqs (i) & (ii)
\n" ); document.write( "S, or speed of canoe, in still water = \"10%2F2\", or 5 mph\r
\n" ); document.write( "\n" ); document.write( "5 – C = 4 ------- Substituting 5 for S in eq (i)
\n" ); document.write( "– C = 4 – 5
\n" ); document.write( "– C = – 1
\n" ); document.write( "C, or speed of current = \"%28-+1%29%2F%28-+1%29\", or \"highlight_green%281%29\" mph
\n" ); document.write( "You can do the check!!
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