document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935954>Question 935954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive integers such that the sum of the three is equal to 2 times more the sum of the first two integers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569360 by </B><A HREF=/tutors/aboutme.mpl?userid=cornelius.bayler><B>cornelius.bayler(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cornelius.bayler><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = first<BR>\n" );
document.write( "x + 1 = second<BR>\n" );
document.write( "x + 2 = third   {consecutive integers increase by 1}\r<BR>\n" );
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document.write( "x + x + 1 + x + 2 = 2(x + x + 1) {sum of the three is equal to 2 times the sum of first two}<BR>\n" );
document.write( "3x + 3 = 2(2x + 1) {combined like terms}<BR>\n" );
document.write( "3x + 3 = 4x + 2 {used distributive property}<BR>\n" );
document.write( "x = 1 {subtracted 3x and subtracted 2 from each side}<BR>\n" );
document.write( "x + 1 = 2 {substituted 1, in for x, into x + 1}<BR>\n" );
document.write( "x + 2 = 3 {substituted 1, in for x, into x + 2}\r<BR>\n" );
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document.write( "1, 2, and 3 are the three consecutive integers<BR>\n" );
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