document.write( "Question 935952: Find the dimensions of a rectangle whose perimeter is 52 and the area is 96 \n" ); document.write( "
Algebra.Com's Answer #569349 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
\"P=2%28l%2Bw%29=52\"
\n" ); document.write( "\"lw=96\"\r
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\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"l=96%2Fw\"
\n" ); document.write( "\"l%2Bw=26\"\r
\n" ); document.write( "\n" ); document.write( "\"96%2Fw%2Bw=26\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"w%5E2-26w%2B96=0\"\r
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\n" ); document.write( "\n" ); document.write( "with the solution:\r
\n" ); document.write( "\n" ); document.write( "\"w=13+-+sqrt%2873%29\"\r
\n" ); document.write( "\n" ); document.write( "\"l=13+%2B+sqrt%2873%29\"
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