document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935878>Question 935878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe took 3 hours to drive from town A to town B and drove back using the same route in 2 hours. Given that he travelled 30km/h faster in his return journey from town B, how far was town A from town B?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569319 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Joe took 3 hours to drive from town A to town B and drove back using the same route in 2 hours. Given that he travelled 30km/h faster in his return journey from town B, how far was town A from town B? <BR>\n" );
document.write( "***<BR>\n" );
document.write( "let x=speed from town A to town B<BR>\n" );
document.write( "x+30=speed of return journey<BR>\n" );
document.write( "distance=travel time*speed(same for both directions)<BR>\n" );
document.write( "3x=2(x+30)<BR>\n" );
document.write( "3x=2x+60<BR>\n" );
document.write( "x=60<BR>\n" );
document.write( "distance=3x=180<BR>\n" );
document.write( "how far was town A from town B? 180 miles </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );