document.write( "Question 935921: 5 stdnts to be chosen in a chess club from 6 boys and 8 girls. How many ways it is possible to form the comittee if 3 of the boys are cousins and are either all in the team or none? \n" ); document.write( "
Algebra.Com's Answer #569312 by Edwin McCravy(20054)![]() ![]() You can put this solution on YOUR website! 5 students to be chosen in a chess club from 6 boys and 8 girls. How many ways is \n" ); document.write( "it possible to form the comittee if 3 of the boys are cousins and are either all \n" ); document.write( "in the team or none are? \n" ); document.write( " \r\n" ); document.write( "Case 1: We choose all 3 cousins.\r\n" ); document.write( "\r\n" ); document.write( "Then we have the other 3 boys remaining and 8 girls. That's 11 people, but we\r\n" ); document.write( "have only 2 more to choose, so that's C(11,2) ways.\r\n" ); document.write( "\r\n" ); document.write( "Case 2: We do not choose any of the three cousins. As before we have the other\r\n" ); document.write( "3 boys and the 8 girls to choose from. That's 11 people, but this time we must\r\n" ); document.write( "choose all 5 from the 11, so that's C(11,5) ways.\r\n" ); document.write( "\r\n" ); document.write( "Answer C(11,2)+C(11,5) = 55+462=517 ways.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |