document.write( "Question 935929: Please help me with this question.
\n" ); document.write( "A tangent to the parabola x^2 = 16y is perpendicular to the line x - 2y - 3 = 0 .find the equation of this tangent and the coordinate of the point of conduct
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Algebra.Com's Answer #569298 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"-2y=-x%2B3\"
\n" ); document.write( "\"y=x%2F2-3%2F2\"
\n" ); document.write( "You want a slope of the desired line to be \"-2\", negative reciprocal of that slope. You do not know the y-intercept of \"y=-2x%2Bk\". You want THIS line to intersect the parabola AT ONE POINT, ....\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=16%28-2x%2Bk%29\"
\n" ); document.write( "\"x%5E2=-32x%2B16k\"
\n" ); document.write( "\"x%5E2%2B32x-16k=0\", you need discriminant of this to be 0. This will ensure the intersection will be ONE POINT.\r
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\n" ); document.write( "\n" ); document.write( "\"%28-32%29%5E2-4%2A%28-16k%29=0\"
\n" ); document.write( "\"1024%2B64k=0\"
\n" ); document.write( "\"64k=-1024\"
\n" ); document.write( "\"highlight%28k=-16%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now you have the line \"y=-2x-16\" and you want to know the intersection of this with the parabola \"x%5E2=16y\".
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\n" ); document.write( "\"x%5E2=16%28-2x-16%29\"
\n" ); document.write( "\"x%5E2=-32x-256\"
\n" ); document.write( "\"x%5E2%2B32x%2B256=0\"
\n" ); document.write( "\"%28x%2B16%29%5E2=0\"
\n" ); document.write( "THIS means, \"highlight%28x=-16%29\" and the corresponding coordinate y is \"y=-2%2A%28-16%29-16\"
\n" ); document.write( "\"y=32-16\"
\n" ); document.write( "\"highlight%28y=16%29\"\r
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\n" ); document.write( "\n" ); document.write( "NEXT:
\n" ); document.write( "What is the line with slope \"-2\" and with the point (-16,16) ?
\n" ); document.write( "Use the point-slope form equation for a line to form the equation of this line.
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