document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935922>Question 935922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A small spherical light source is 1.8m above the centre point of a square table of a side of 2 figure 1. the illuminance E at the centre point of the table is 300 lx.\r<BR>\n" );
document.write( "\n" );
document.write( "calculate the ecrnr at the tip of the table. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #569286 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=569286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Calculate the distance from the bulb to the corner of the table (I assume that's what you mean by tip).<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R%5E2=1.8%5E2%2B1%5E2%2B1%5E2 ALIGN=MIDDLE  ALT=\"R%5E2=1.8%5E2%2B1%5E2%2B1%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R%5E2=3.24%2B1%2B1 ALIGN=MIDDLE  ALT=\"R%5E2=3.24%2B1%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=R%5E2=5.24 ALIGN=MIDDLE  ALT=\"R%5E2=5.24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Illuminance is inversely proportional to the square of the distance.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k%2F1.8%5E2=300 ALIGN=MIDDLE  ALT=\"k%2F1.8%5E2=300\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k%2F5.24=X ALIGN=MIDDLE  ALT=\"k%2F5.24=X\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=X=300%283.24%2F5.24%29 ALIGN=MIDDLE  ALT=\"X=300%283.24%2F5.24%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=X=185.5 ALIGN=MIDDLE  ALT=\"X=185.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=lx ALIGN=MIDDLE  ALT=\"lx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Since the distance from the source to the edge of the table is 1.8 down, 1 up, and 1 over, the source is no longer directly over the point but at an angle,<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+theta ALIGN=MIDDLE  ALT=\"+theta\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28theta%29=sqrt%281%5E2%2B1%5E2%29%2F1.8 ALIGN=MIDDLE  ALT=\"tan%28theta%29=sqrt%281%5E2%2B1%5E2%29%2F1.8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta=38.2 ALIGN=MIDDLE  ALT=\"theta=38.2\"   DISABLED_style= \"max-width:90%; height:auto;\" > degrees<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=En=X%2Acos%28theta%29=185.5%2Acos%2838.2%29=145.7 ALIGN=MIDDLE  ALT=\"En=X%2Acos%28theta%29=185.5%2Acos%2838.2%29=145.7\"   DISABLED_style= \"max-width:90%; height:auto;\" > lx </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );