document.write( "Question 79323: A square room has a square rug in it. The area of the room not covered by the rug is 51 sq feet. The sum of the lenght of a side of the rug and the lenght of a side of the room is 17 feet. Find the dimensions of the room.\r
\n" ); document.write( "\n" ); document.write( "I know Area=LenghtxWidth and Perimeter is 2Lenght + 2 Width, but I can't figure out this one. Please help.
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Algebra.Com's Answer #56928 by stanbon(75887)\"\" \"About 
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A square room has a square rug in it. The area of the room not covered by the rug is 51 sq feet. The sum of the lenght of a side of the rug and the lenght of a side of the room is 17 feet. Find the dimensions of the room.
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\n" ); document.write( "Draw the picture of the square room with the square rug in it.
\n" ); document.write( "Hint: put the square in the corner of the square room.
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\n" ); document.write( "Let a side of the square rug be x ft.
\n" ); document.write( "Let a side of the square room be y ft.
\n" ); document.write( "EQUATION:
\n" ); document.write( "x+y=17 ft
\n" ); document.write( "y=17-x
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\n" ); document.write( "The area of the square room is y^2=(17-x)^2
\n" ); document.write( "The area of the square rug is x^2
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\n" ); document.write( "EQUATION:
\n" ); document.write( "Area of room - Area of rug = 51 sq ft.
\n" ); document.write( "(17-x)^2-x^2=51
\n" ); document.write( "17^2-34x+x^2-x^2=51
\n" ); document.write( "17^2-51=34x
\n" ); document.write( "x=238/34
\n" ); document.write( "x=7 ft (the rug is 7'x7'
\n" ); document.write( "17-x=17-7=10 (the room is 10'x10')
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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